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25p^2-45p=0
a = 25; b = -45; c = 0;
Δ = b2-4ac
Δ = -452-4·25·0
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2025}=45$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-45}{2*25}=\frac{0}{50} =0 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+45}{2*25}=\frac{90}{50} =1+4/5 $
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